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PHP Function to calculate time remaining

Many times it is required for us to calculate the time remaining and display it in a very understandable format like days,weeks,hours etc.
Here is a function i wrote to do the same.

PHP Code:
//FUNCTION FOR TIME LEFT
function time_left($integer)
{

$seconds=$integer;

if ($seconds/60 >=1)

{

$minutes=floor($seconds/60);

if ($minutes/60 >= 1)

{ # Hours

$hours=floor($minutes/60);

if ($hours/24 >= 1)

{ #days

$days=floor($hours/24);

if ($days/7 >=1)

{ #weeks

$weeks=floor($days/7);

if ($weeks>=2) $return="$weeks Weeks";

else $return="$weeks Week";

} #end of weeks

$days=$days-(floor($days/7))*7;

if ($weeks>=1 && $days >=1) $return="$return, ";

if ($days >=2) $return="$return $days days";

if ($days ==1) $return="$return $days day";

} #end of days

$hours=$hours-(floor($hours/24))*24;

if ($days>=1 && $hours >=1) $return="$return, ";

if ($hours >=2) $return="$return $hours hours";

if ($hours ==1) $return="$return $hours hour";

} #end of Hours

$minutes=$minutes-(floor($minutes/60))*60;

if ($hours>=1 && $minutes >=1) $return="$return, ";

if ($minutes >=2) $return="$return $minutes minutes";

if ($minutes ==1) $return="$return $minutes minute";

} #end of minutes

$seconds=$integer-(floor($integer/60))*60;

if ($minutes>=1 && $seconds >=1) $return="$return, ";

if ($seconds >=2) $return="$return $seconds seconds";

if ($seconds ==1) $return="$return $seconds second";

$return="$return.";

return $return;

}

/* Returns a string of the amount of time the integer (in seconds) refers
to.

$timeleft=time_left(86400);

$timeleft='1 day'.

Will not return anything higher than weeks. False if $integer=0 or fails.

*/
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